To get a rough view of how many rows, total, used and unused space each table has, in a sql server database you can run the following query:
USE {Database_Name};
GO
SELECT
t.Name AS TableName,
s.Name AS SchemaName,
p.Rows AS RowCounts,
SUM(a.total_pages) * 8 AS TotalSpaceKB,
SUM(a.used_pages) * 8 AS UsedSpaceKB,
(SUM(a.total_pages) - SUM(a.used_pages)) * 8 AS UnusedSpaceKB
FROM
sys.tables t
INNER JOIN sys.indexes i ON t.object_id = i.object_id
INNER JOIN sys.partitions p ON i.object_id = p.object_id AND i.index_id = p.index_id
INNER JOIN sys.allocation_units a ON p.partition_id = a.container_id
LEFT OUTER JOIN sys.schemas s ON t.schema_id = s.schema_id
WHERE
t.Name NOT LIKE 'dt%'
AND t.is_ms_shipped = 0
AND i.object_id > 255
GROUP BY
t.Name, s.Name, p.Rows
ORDER BY
t.Name;
GO
Another way is using the stored procedure `sp_spaceused` which displays the number of rows, disk space reserved, and disk space used by a table, indexed view, or Service Broker queue in the current database, or displays the disk space reserved and used by the whole database.
Display disk space information about a table
USE {database_name};
GO
EXEC sp_spaceused N'{dbo}.{table_name}';
GO
Display disk space information for all tables at once
USE {database_name};
GO
sp_msforeachtable N'EXEC sp_spaceused [?]';
GO
Space used by indexes
If you want to find how much space is used by indexes on the tables of a database you can use the following query:
SELECT OBJECT_NAME(i.object_id) AS TableName, i.name AS IndexName, i.index_id AS IndexID, 8 * SUM(a.used_pages) AS 'Indexsize(KB)' FROM sys.indexes AS i JOIN sys.partitions AS p ON p.object_id = i.object_id AND p.index_id = i.index_id JOIN sys.allocation_units AS a ON a.container_id = p.partition_id GROUP BY i.OBJECT_ID, i.index_id, i.name ORDER BY OBJECT_NAME(i.object_id), i.index_id
Thank you! Very helpful, it let me track down an issue quickly.
quick and easy solution.